Question

Form a cubic polynomial with zeroes 3 , 2 and -1

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Answer 1

Hello dear user ....

Solution is here ...
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If the zeros of the cubic Polynomial are 3, 2 and -1 than the cubic Polynomial can be found as

${x}^{3} - (a + b + c) {x}^{2} + (ab + bc + ca)x - abc$

Let ,
$a = 3 \: \ \: \: b = \: 2 \: \: and \: \: c = - 1$

Substituting , the value in 1 , we get

${x}^{3} - (3 + 2 + ( - 1)) {x}^{2} + (6 - 2 - 3)x - ( - 6) \\ \\ = > {x}^{3} + 5 {x}^{2} + x + 6$


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Hope it's helps you.
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