Form a cubic polynomial with zeros 3,2 amd -1
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Answered by
66
Hello friend
Let the cubic polynomial be p(x)
It's zeros are 3,2,-1
So the factors will be (x-3),(x-2),(x+1)
A cubic polynomial will at most have three zeros
So by multiplying all its three factors, we will get the polynomial
(x-3)(x-2)(x+1)
=(x²-2x-3x+6)(x+1)
=(x²-5x+6)(x+1)
=x³+x²-5x²-5x+6x+6
=x³-4x²+x+6
Here we got the polynomial
Hope it helps!
Let the cubic polynomial be p(x)
It's zeros are 3,2,-1
So the factors will be (x-3),(x-2),(x+1)
A cubic polynomial will at most have three zeros
So by multiplying all its three factors, we will get the polynomial
(x-3)(x-2)(x+1)
=(x²-2x-3x+6)(x+1)
=(x²-5x+6)(x+1)
=x³+x²-5x²-5x+6x+6
=x³-4x²+x+6
Here we got the polynomial
Hope it helps!
Answered by
3
this is the another way to do it
hope it helped you
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