Question

Form a pair of linear equations for each of the following problems and find their solution The ratio of incomes of two persons is 9 : 7 and the ratio of their expenditures is 4:3. If each of them manages to save 2000 per month then find their monthly income.​

Answer 1

Answer:

answer is 18000,14000

Step-by-step explanation:

hope it helps you

Answer 2

Answer:

Step-by-step explanation:

Given,

The ratio of incomes of two persons is 9:7 and the ratio of their expenditures is 4:3.

Each of them manages to save 2000 per month.

To Find,

Their monthly income.​

Solution,

Let us assume their incomes be 9x and 7x.

And their expenditures be 4y and 3y respectively.

According to the question,

⇒ 9x - 4y = 2000 .... (i)

⇒ 7x - 3y = 2000 .... (ii)

From eq (i), we get

$\implies x = \frac{(2000 + 4y)}{9} ...(iii)$

Now, putting x's value in eq (ii), we get

⇒ 7x - 3y = 2000

$\implies7\times\frac{(2000+4y)}{9}-3y=2000$

$\implies\frac{(14000+28y)}{9}-3y=2000$

$\implies\frac{14000+28y-27y}{9}=2000$

$\implies14000+y=18000$

$\implies y=18000-14000$

$\implies \textbf{y = 4000}$

Now, putting y's value in eq (iii), we get

$\implies x = \frac{(2000 + 4y)}{9}$

$\implies x = \frac{2000+4\times(4000)}{9}$

$\implies x = \frac{2000+16000}{9}$

$\implies x = \frac{18000}{9}$

$\implies \textbf{x = 2000}$

Now, Their monthly income,

Monthly income of 1st person = 9x = 9 × 2000 = 18000.

Monthly income of 2nd person = 7x = 7 × 2000 = 14000.