Question

® form a polynomial whose zerses are 2, -2​

Answer 1

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Answer 2

Step-by-step explanation:

$\alpha = 2 \\ \beta = - 2 \\ sum \: of \: zeros = \alpha + \beta \\ \: \: \: \: \: \: \: = 2 + ( - 2) \\ \: \: \: \: \: \: \: \: = \: \: 0 \: \\ \alpha \beta = 2 \times ( -2 ) \\ \: \: \: \: \: \: \: = - 4 \\ required \: quadratic \: equation \\ {x}^{2} - ( \alpha + \beta )x + \alpha \beta = 0 \\ {x}^{2} - 0 \times x + ( - 4) = 0 \\ {x}^{2} - 4 = 0 \: ans$