Question

form a quad poly whose one zero is 8 and product is -56​

Answer 1

Hlo..

here is the solution

let,

alpha=8

alpha×beeta=-56

8×B=-56

B=-56/8

B=-7

here,

A=8

B=-7

as we know

A(alpha)=-b/a

= -(8)/1

B(BEETA)=c/a

=(-7)/1

therefore

a=1, b=8 ,c=-7

by the quadric equation ax^2+bx+C

x^2+8x-7

the the equation for the zero's is

x^2+8x-7

Thank you