Question

form a quadratic equation whoes zeroes are 2/3 and minus1/3

Answer 1

Answer:9x^2+12x-2

Step-by-step explanation:

2/3 or -1/3

x=2/3 or x=-1/3

3x=2 , 3x=-1

3x-2=0 , 3x+1=0

(3x-2)(3x+1)=0

3x(3x-2)-2(3x+1)

9x^2-6x-6x-2

9x^2+12x-2

hope it helps...mark me a s brainliest

Answer 2

Answer:

the quadratic equation is :

9x^2 -3x -2 = 0

Step-by-step explanation:

let the zeroes are

α = 2/3 and   = -1/3

therefore ,  α+β = 2/3 +-1/3 = 1/3

                   αβ = 2/3*-1/3 = -2/9

the quadratic equation are :

x^2 -(α+β )x +  αβ = 0

x^2 -1/3x +-2/9 = 0

9x^2 -3x -2 = 0