Question

Form a quadratic equation whose one zero is 3+√5 and sum of zeroes is 6.

Answer 1

Answer:

x^2 -6x +4 = 0

Step-by-step explanation:

one zero = 3 + root5

let say second zero = p

sum of zeroes = 6

3 + root5 + p = 6

p = 3 - root5

(x - oneroot)(x-2ndroot)= 0

(x - 3 - root5)(x -3 + root5) = 0

(x-3)^2 - (root5)^2 =0

x^2 -6x + 9 -5= 0

x^2 -6x +4 = 0