Form a quadratic equation whose one zero is 4 and the product of the zeroes is 28.
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Answer:
quadratic equation whose one zero is 4 and the product of the zeroes is 28 is
x^2 +4x +28
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Step-by-step explanation:
let X and y be the zeroes
X=4
product of zeroes=28
X×y=28
4×y=28
y=28/4
y=7
X=4
y=7
Sum of the zeroes= 4+7=11
AND...
product of the zeroes is 28 as mentioned in the question
THEREFORE
the required quadratic equation is
X²-11X+28
HOPE IT HELPS U
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