Question

form a quadratic equation whose root is 2 and -5​

Answer 1

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$roots \: are \: = 2 \: and \: - 5 \\ so \: (x - 2) \: and \: (x + 5) \: are \: the \: factors \: of \: p(x) \\ now \: (x - 2) \times (x + 5) \\ = {x}^{2} - 2x + 5x - 10 \\ = {x}^{2} + 3x - 10 \\ \\ \\ \\ hence \: the \: quadraic \: equation \: is \: = \: {x}^{2} + 3x - 10$

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Answer 2

Answer:

x^2+3x-10

Step-by-step explanation:

sum of the root =2+(-5)= -3

product of the root=2×-5= -10

quadratic equations=x^2-(sum of the root)+product of the root

x^2+3x-10

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