Question

form a quadratic equation whose roots are (1+√3)&(1-√3)​

Answer 1

Answer:

$Required\: Quadratic\: equation:\\x^{2}-2\sqrt{3}x+3=0Step-by-step explanation:Let\: \alpha \:and \: \beta \\are \: two \: roots \: of \:a \\quadratic\: equation. \alpha = \sqrt{3}\\\beta =\sqrt{3}\:(given) Form \:of\:a\: Quadratic\\equation \:whose\:roots \:are\\\alpha \:\beta \:is x^{2}-(\alpha+\beta)x+\alpha\beta=0\implies x^{2}-(\sqrt{3}+\sqrt{3})x+\sqrt{3}\times \sqrt{3}=0\implies x^{2}-2\sqrt{3}x+3=0Therefore, Required\: Quadratic\: equation:\\x^{2}-2\sqrt{3}x+3=0•••♪$Hope it helps you

Step-by-step explanation:

Answer 2

Answer:

pls mark as brainliest...if helpful