Question

form a quadratic equation whose roots are 3+√2 and 3-√2​

Answer 1

$\sf{Answer}$

Step by step explanation:-

As they given,

3+√2 and 3-√2 are roots of Q.E

We have to find Quadratic equation

The required Quadratic equation is

x² -(sum of roots) x + product of roots

Sum of roots =

3+√2 + 3-√2

3 + 3+√2 -√2

6

Sum of roots = 6

Product of roots =

(3+√2 ) (3-√2 )

It is in form of (a+b)(a-b) = a²-b²

So,(3+√2 ) (3-√2) = 3² -(√2 )²

= 9 -2

=7

product of roots = 7

So substuite!!

Required Quadratic equation =

x² -(sum of roots) x + product of roots

x² -(6)x + 7

x² -6x +7

So, Required Quadratic equation whose roots are3+√2 and 3-√2 is x²-6x+7

____________________________

Hope my answer helps to u

Thank u :)