Question

Form a quadratic equation whose roots are 3 and -3 respectively

Answer 1

Step-by-step explanation:

given

$\alpha = 3 \: \: and \: \beta = - 3$

the required quadratic equation is

$= {x}^{2} - ( \alpha + \beta )x + \alpha \beta = 0$

→x^2-(3-3)x+(3)(-3)=0

→x^2-9=0