Question

Form a quadratic equation whose roots are -3 and 4

Answer 1

Answer:

x^2-7x+12=0

Explanation:

If x=3 or4

then,

(x-3)(x-4)=0

x^2-4x-3x+12=0

x^2-7x+12=0

Answer 2

Roots are −3 and 4.

Sum of the roots =−3+4=1  

Product of the roots =−3×4=−12

x^2  − (Sum of the roots)x + (Product of the roots) =0

Required equation is

x^2−x−12=0