Question

Form a quadratic equation whose roots are -3 and 4​

Answer 1

GIVEN:

Roots of a quadratic equation = -3 and 4

TO FIND:

The quadratic equation

SOLUTION:

Let the zeroes be a and b

We know that,

The standard form of quadratic equation is,

x² - (a + b)x + ab = 0

Sum of zeroes = -3 + 4 = 1

Product of zeroes = -3 × 4 = -12

Now,

==> x² - (1)x + (-12) = 0

==> x² - x - 12 = 0

Therefore, the required quadratic equation is x² - x - 12 = 0.

Answer 2

Answer:

to form a quadratic equation with -3 and 4 ,

the formula is x2-(sum of the roots)x +(product of the roots)=0

therefore,

x2-(-3+4)x+-3×4=0

x2- (-1)x -12=0

x2-+x-12=0