Question

Form a quadratic equation whose sum and product are -3 and 2

Answer 1

AnswEr:

$\bold{\underline{\sf{\red{\;\;Given:-\;\;}}}}$

$\dag$ Sum of Zeroes = -3

$\dag$ Product of Zeroes = 2

We know that,

Sum of Zeroes = $\sf\; (\alpha \; + \; \beta)$

Product of Zeroes = $\sf\; (\alpha \; \beta)$

$\rule{150}3$

$\bold{\underline{\sf{\red{\;\; Using\; Formula:-\;\;}}}}$

Here,

• $\sf (\alpha + \beta)\; = \; -3$
• $\sf (\alpha\; \beta)\; = \; 2$

$\dag\large{\underline{\boxed{\sf{\pink{x^2 - (\alpha \; + \; \beta)x + (\alpha\; \beta)}}}}}$

Now,

$\longrightarrow\sf\; x^2 + 3x + 2$

$\large{\underline{\boxed{\sf{\pink{x^2 + 3x + 2}}}}}$

So, Our Quadratic Equation is x² + 3x + 2.

$\rule{150}3$

Answer 2

$\huge \fcolorbox{red}{pink}{Solution :)}$

Given ,

Sum of roots = -3

Product of roots = 2

We know that ,

$\large \mathtt{\fbox{ {(x)}^{2} - (sum \: of \: roots)x + (product \: of \: roots) }}$

Substitute the known values , we get

(x)² - (-3)x + 2

(x)² + 3x + 2

Hence , the quadratic equation is (x)² + 3x + 2 = 0

______________ Keep Smiling ☺