Question

form a quadratic equation with roots 3 and 4​

Answer 1

Step-by-step explanation:

Let alpha=3 and beta=4

So, Equation will be,

${x}^{2} - ( \alpha + \beta )x + \alpha \beta \\ {x}^{2} - (4 + 3)x + (4 \times 3) \\ {x}^{2} - 7x + 12$

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Answer 2

Answer:

heya mate... :)

Given, Two roots of the equation are 3 and 4

So, Formula for forming equation is :

$x ^{2} - (sum \: of \: roots)x + (product \: of \: roots) = 0$

Hence, Sum of roots = 3 + 4 = 7

Product of roots = 3 * 4 = 12

So putting back to formula ⤴⤴ , we get

$x ^{2} - 7x + 12 = 0$

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