Question

form a quadratic pilynomial whose zeros are 4 and -3​

Answer 1

Answer:

$\large{\underline{\boxed{\sf x^2 - x - 12}}}$

Step-by-step explanation:

Let the zeroes of the quadratic polynomial be α and β respectively.

Sum of zeroes = α + β

⇒ α + β = 4 + (-3)

⇒ α + β = 1

Product of zeroes = αβ

⇒ αβ = 4 * (-3)

⇒ αβ = - 12

Now, we know that the quadratic polynomial is given by -

= x² - (α + β)x + αβ

= x² - x - 12

Hence, the required quadratic polynomial is (x² - x - 12).

Answer 2

Step-by-step explanation:

sum of zero =4-3=1

product of zero =4×-3=-12

formula of quadratic polynomial

X2-(sum of zero)x +product of zero

x2-1x-12