Question

form a quadratic polyinomial where zero are 2and 3​

Answer 1

Step-by-step explanation:

Let the zeros are=$\sf \alpha,\beta$

Zeros are 2 and 3

Formula :-

$\boxed{\sf x^2-(\alpha+\beta)x+\alpha\beta=0}$

• substitute the values

$\qquad\sf {:}\rightarrowtail x^2-(2+3)x+2×3=0$

$\qquad\sf {:}\rightarrowtail x^2-5x+6=0$