Question

form a quadratic polynomial if sum of its zeros is 6and products of its zeros is -3​

Answer 1

Answer:

given,

sum of zeroes , S = 6

and , product of zeroes , P = -3

so,

required quadratic equation is

x²- ( S)x + P = 0

or ,

x² - ( 6)x + ( -3) = 0

or , x² -6x - 3 = 0.

$.$

Answer 2

Answer

x²-sx+p

x²-6x+3

sum of zeros=-b/a =-(-6)/1=6

products of zeros=c/a=3/1=3