form a quadratic polynomial if sum of its zeros is 6and products of its zeros is -3
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given,
sum of zeroes , S = 6
and , product of zeroes , P = -3
so,
required quadratic equation is
x²- ( S)x + P = 0
or ,
x² - ( 6)x + ( -3) = 0
or , x² -6x - 3 = 0.
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Answer
x²-sx+p
x²-6x+3
sum of zeros=-b/a =-(-6)/1=6
products of zeros=c/a=3/1=3
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