Question

form a quadratic polynomial when its zeros are minus 3 upon 2 as alpha beta equals to 7 upon 3

Answer 1

Heya. .☺

Ur ans.
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➡ Quadratic Polynomial = x^2 - (Sum of zeroes)x + Product of zeroes

Here ,
$\alpha = - 3 \div 2$
$\beta = 7 \div 3$
Therefore ,

Quadratic Polynomial =

${x}^{2} -( - 3 \div 2 + 7 \div 3) x+ ( - 3 \div 2 \times 7 \div 3)$

${x}^{2} - ( 5 \div 6) x+ ( - 7 \div 2)$

$1 \div 6(6 {x}^{2} - 5x - 7 \div 2)$

$therefore \: the \: \: quadatic \: equation \: is$

➡ ${6}x^{2} - 5x - 7 \div 2$

◾◾Hope it helps ◾◾

Answer 2

Hiii friend,

Alpha = -3/2

Beta = 7/3

sum of zeros = Alpha+ Beta = -3/2+7/3 = -3×3 +. 7×2 ÷6 = -9+14/6 = 5/6

Product of zeros = (Alpha × Beta) = -3/2 × 7/3 = -7/2

Therefore,

Quadratic polynomial = X²-(Alpha + Beta)X + Alpha × Beta = X²-(5/6)X + (-7/2) = X²-5X/6-7/2 = 6X²-5X-21

Hence,

The QUADRATIC POLYNOMIAL = 6X²-5X-21

HOPE IT WILL HELP YOU... :)