Question

Form a Quadratic polynomial whose sum of zeros is -4 and product of zeros is 8.​

Answer 1

Answer:

x²-4x+8

Step-by-step explanation:

x²+(sum of zeroes) + product of zeroes

Answer 2

Given

• Sum of zeroes (α + ß) = -4
• Product of zeroes (αß) = 8

To find

• Quadratic polynomial.

Solution

• Let that quadratic polynomial be p(x).

★ We know that

$\underline{\boxed{\tt{p(x) = x^2 - (sum\: of\: zeroes)x + (product\: of\: zeroes)}}}$

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$\tt:\implies\: \: \: \: \: \: \: \: {p(x) = x^2 - (-4)x + 8}$

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$\tt:\implies\: \: \: \: \: \: \: \: {p(x) = x^2 + 4x + 8}$

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$\tt\longmapsto{Quadratic\: polynomial = x^2 + 4x + 8}$

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$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{\bigstar{\tt{Extra\: shots{\bigstar}}}}$

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Quadratic polynomial

$\sf\pink{⟶}$ A polynomial in the form of ax² + bx + c where a, b and c are real numbers, and a 0 is known as a quadratic polynomial.

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