Question

Form a Quadratic polynomial whose sum of zeros is 4 and product of zeros is 8​

Answer 1

Given :-

• Sum of zeroes = 4
• Product of zeroes = 8

To Find :-

• Quadratic Polyniomial = ?

Answer :-

• x² - 4x + 8

Explaination :-

We know the sum and product of the zeroes of this quadratic polyniomial.

Formula to form a quadratic polynomial:

• p(x) = k[x² - (Sum of zeroes)x + Product of zeroes]

Here, Sum of zeroes = α + β= 4 and product of zeroes = αβ = 8

Now, substituting the given values in above formula we get :

$:\implies \sf p(x) = k\bigg\lgroup x^2 - (\alpha + \beta)x + \alpha \beta\bigg\rgroup$

$:\implies \sf p(x) = k\bigg\lgroup x^2 - (4)x + 8\bigg\rgroup$

$:\implies \sf p(x) = \bigg\lgroup x^2 - 4x + 8\bigg\rgroup$

Therefore,x² - 4x + 12 is the quadratic polyniomial whose sum of zeroes is 4 and product of zeroes is 8.

Answer 2

Answer:

The correct answer of this question is x2 - 4x + 12 h

Step-by-step explanation:

Given - Quadratic polynomial.

To Find - Form a Quadratic polynomial whose sum of zeros is 4 and product of zeros is 8​.

As a result, the quadratic polyniomial x2 - 4x + 12 has a sum of zeroes of 4 and a product of zeroes of 8.

Quadratics can be defined as a second-degree polynomial equation with a minimum of one squared term.

Because quadratum is the Latin word for square and the area of a square with side length x equals x2, a polynomial equation with exponent two is called a quadratic ("square-like") problem.

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