form a quadratic polynomial whose zero is 7+2√2
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since irrational roots lie in pairs therefore second root should be 7–2√2
hence equation is {x–(7+2√2)}×{x–(7–2√2)} = 0
equation is x^2 –14x +41 = 0.
hence equation is {x–(7+2√2)}×{x–(7–2√2)} = 0
equation is x^2 –14x +41 = 0.
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