Question

Form a quadratic polynomial whose zeroes are 1/2 and -3/7 ??? plz give the answer fast :) i will mark the brainliest :)

Answer 1

Step-by-step explanation:

given that

zeroes are 1/2 and -3/7

we know that

$sum \: of \: zeroes \: = \alpha + \beta = - ( \: cofficient \: of \: x) \div (cofficient \: of \: x {}^{2}$

1/2 + (-3/7) = (-b) / a

1/14 = - b / a

so , b = -1

a = 14

product of zeroes = 1/2 × -3/7 = constant term / coefficient of x²

-3/14 = c/a

so, c = -3

a = 14

so quadratic equation is ...

14x² -x -3