Question

Form a quadratic polynomial whose zeroes are 3 + √2 and 3 – √2.​

Answer 1

Answer:

Given zeros of polynomial are 3±2

Let α,β be zeros of polynomial 

then

α+β=3+2+3−2=6 ________ (1)

& αβ(3+2)(3−2)

αβ=9−32+32−2=7 _________ (2)

then

quadratic equation is

x2−(α+β)x+αβ=0

From (1) & (2)

[x2−6x+7=0]

Answer 2

Step-by-step explanation:

For the quadratic equation if one root is 2+ 3

Other root is 2− 3

Sum of roots=2+ 3 +2− 3=4

Product of roots=(2+ 3 )(2− 3)=4−3=1

∴Quadratic equation is x2−4x+1=0