Question

Form a quadratic polynomial, whose zeroes are 3 and -4.
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Answer 1

Step-by-step explanation:

$\alpha = 3 \: \: and \: \: \beta = - 4 \\ \\ = x ^{2} + ( \alpha + \beta )x + \alpha \beta \\ \\ = {x}^{2} + (3 + ( - 4))x + 3( - 4) \\ \\ = x^{2} - 1x - 12$

Hope it helps...

Answer 2

Answer:

Step-by-step explanation:

x² + ( a +b ) x + ab

x² + (-3 +4) x + (-3 × 4)

x² + x -12