Question

Form a quadratic polynomial whose zeroes are
3-V3 3+3
and
5​

Answer 1

Answer:

x^2-11x +30

Step-by-step explanation:

Roots : (3-root 3) ( 3+ root 3) and 5

alpha = (3-root 3) (3+root 3) = (3)^2 - (root 3)^2=9-3= 6

beeta=5

alpha + beeta =-b/a

6+5 = 11=-b/a

alpha * beeta = c /a

6*5= 30 = c/a

a=1, b=-11, c=30

x^2-11x +30 is the quadratic polynomial

Hope this answer is helpful