Question

Form a quadratic polynomial
whose zeroes
are 4 &-5​

Answer 1

Answer:

Hope it helps you .

Step-by-step explanation:

Equation=

${x}^{2} - sx + p = 0 \\ {x}^{2} + - ( - 5 + 4)x - 5 \times 4 = 0 \\ {x}^{2} + x - 20 = 0$

Answer 2

Answer :-

• x² + x - 20

Given :-

• Zeroes of a quadratic polynomial are 4 and -5.

To Find :-

• The quadratic polynomial.

Solution :-

Sum of zeroes :-

4 + (-5)

→ 4 - 5

→ -1

Product of zeroes :-

4 × (-5)

→ -20

As we know that

Formula for finding quadratic polynomial is

x² - (sum of zeroes)x + product of zeroes

→ x² - (-1)x + (-20)

→ x² + x - 20

Hence, the quadratic polynomial is x² + x - 20