Question

form a quadratic polynomial whose zeros are -3/2 and root 2 also find its zero​

Answer 1

$\alpha + \beta = \frac{- 3}{2} \\ \alpha \beta = 2 \\ x {}^{2} - ( \alpha + \beta ) x+ \alpha \beta \\ x {}^{2} -( - \frac{3}{2} )x + 2 = 0\\ x {}^{2} + \frac{3}{2} x + 2 = 0 \\ \frac{2x { }^{2} + 3x + 4}{2} = 0 \\ 2x {}^{2} + 3x + 4 = 0$