Question

form a quadratic polynomial whose zeros are 7+2√2 and 7-2√2​

Answer 1

Step-by-step explanation:

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Answer 2

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Given:

zeroes of the polynomial (7+ 2√2), (7-2√2)

To find:

The polynomial.

Let the zeroes be alpha(α) and beta(ẞ) respectively.

⠀⠀⠀⠀⠀⠀⠀⠀α+ẞ = 7+7 = 14

⠀⠀⠀⠀⠀⠀α×ẞ = (7+2√2)(7-2√2)

⠀⠀⠀⠀⠀⠀⠀⠀⠀α×ẞ = 49-8

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀α×ẞ = 41

To find the polynomial ;;

x² - (α+ẞ)x + αẞ (substituting the values)

x²- 14x+ 41

Hence, the required polynomial is x²- 14x+ 41.