Question

form a quadratic polynomial whose zeros are 7 + root 5 and 7 minus root 5 ​

Answer 1

Answer:

x² + 7√5 - 7√5 = 0

MARK BRAINLIEST...

Answer 2

Answer:

$\large \bold\red{{x}^{2} - 14x + 44}$

Step-by-step explanation:

Given,

The roots of a quadratic equations are,

$7 + \sqrt{5}$

And

$7 - \sqrt{5}$

Therefore,

Sum of roots,

$= 7 + \sqrt{5} + 7 - \sqrt{5} \\\\ = 14$

And,

Product of roots,

$= (7 + \sqrt{5} )(7 - \sqrt{5} ) \\\\ = {(7)}^{2} - {( \sqrt{5} )}^{2} \\ \\ = 49 - 5 \\ \\ = 44$

Now,

We know that,

Quadratic equation is given by,

$\large \boxed{ \bold{{x}^{2} - (sum \: of \: roots)x + (product \: of \: roots)}}$

Hence,

We get,

The required quadratic equation as,

$\large \bold{{x}^{2} - 14x + 44}$