Question

form a quadratic polynomial whose zeros are as follows first 5 - 6 second 2 + root 3 2 minus root 3​

Answer 1

Answer:

56778×5667889/678=46789

Answer 2

Answer:

yo.......ur answer is

x^2-10x+13

Step-by-step explanation:

(5+2√3) and (5-2√3) are the zeros of the polynomial.

let Alpha =(5+2√3)

and

bets =(5-2√3)

sum of zeros= (Alpha + Beta)

=(5+2√3) + (5-2√3)

=10

Therefore,

The required polynomial

=x^2-(Alpha + Beta) x + Alpha × Beta

=x^2-(10) x + 13

=x^2-10x +13

Hence,

the polynomial is x^2 - 10x + 13

hope this will help you