Question

form a quadratic polynomial whose Zerses are (3+√5) /5 and (3-√5)/5​

Answer 1

Answer:

=x²-6/5+4/25

Step-by-step explanation:

=x²-(sum)x+(product)

sum = (3+√5)/5+(3-√5)/5

=3+√5+3-√5/5

=3+3/5

=6/5

product= (3+√5)/5 ×(3-√5)/5

=9-3√5+3√5-5/25

= 9-5/25

=4/25

=x²-6/5+4/25