Question

Form a quadratic polynomials whose zeros are :
(1) 2+ underroot3, 2-underoot3 (1) & (ii) 3 and -2 (iii) 2/3and -1/3​

Answer 1

Answer:

Zeroes are

$\sqrt{2 } + 3 \: and \: \sqrt{2} - 3$

Polynomial =

$x ^{2} - {sum} \times x + {product}$

$= x^{2} - ( \sqrt{2} + 3 + \sqrt{2} - 3)x + ( \sqrt{2} - 3)( \sqrt{2} + 3)$

$= x^{2} - 2 \sqrt{2 } x + 2 - 9$

$= x ^{2} - 2 \sqrt{2}x - 7$

Since the quadratic polynomial

$= x ^{2} - 2 \sqrt{2} x - 7$

Hence proved...

Hope this answer helps you....