Question

form a quadratic whose zeroes are -4 and 5​

Answer 1

Given :-

• two zeros -4 and 5

To find :-

• quadratic equation

solution :-

value of

a+B= -4+5= 1

value of

aB= -4×5= -20

put value

K(x²-(a+B)x+aB)

k(x²-(1)x-20)

k(x²-x-20)

here ,k is constant

Extra information :-

Formation of polynomial when zeroes are given :-

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1)Type

• constant polynomial

zeroes

• no zeroes

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2)Type

• Linear polynomial

zeroes

• Its zero is. ' a ' because it have only one zero

sum and product

• sum and product in this case is same

Expression

• k[x-a]

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3)Type

• quadratic polynomial

zeroes

• Let a and B it's zeros

sum and product

• sum = a+B
• product =aB

expression

• K(x²-(a+B)x+aB)

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4)Type

• zero polynomial

zeroes

• number zero itself is known as zero polynomial

Sum and product

• do not exist

expression

• p(x)=(0)