Question

Form a quaradic equation whose roots are -3 and 4(1)

Answer 1

Step-by-step explanation:

sum of roots = -3+4=1

product of roots = -3×4

=-12

equation is

x^2 -(1)x+(-12)=0

x^2-x-12=0 is answer obtained

Answer 2

Answer:

x² - x - 12

Step-by-step explanation:

The given roots are   -3  and   4 .

Let  

α  =  -3   and   β  = 4

∴ α  +  β  =  -3 +  4  =  1

and  

α  ×  β  =  -3 ×  4  =  -12

The required quadratic equation is

= x ²  −  ( α + β ) x  +  α  * β  

= x ²  −  (1)x +  (-12 )

=  x² - x - 12