Question

Form all quadratic polynomial whose one zero is 8 and the product of zero is 56

Answer 1

Hi...☺

Here is your answer...✌

Given that,

One zero of polynomial is 8
i.e., α = 8

Also given that,
Product of zeros = 56

α×β = 56

8×β = 56

⇒ β = 7

Sum of zeros ,

α + β = 8 + 7 = 15

Now,

Quadratic polynomial :

⇒ x² - ( α + β )x + αβ

⇒ x² - 15x + 56

HENCE,

The required quadratic polynomial is
x² - 15x + 56

Answer 2

Hii friend,

Let Alpha = 8

Product of zeros = Alpha × Beta

56 = 8 × Beta

Beta = 56/8 = 7


Sum of zeros = (Alpha + Beta) = (8+7) = 15


Therefore,

POLYNOMIAL = X²-(Alpha + Beta)X + Alpha × Beta = X²-15X+56.

Hence,

QUADRATIC POLYNOMIAL = X²-15X+56.


HOPE IT WILL HELP YOU..... :-)