Question

Form an equation for the following situation:
The product of two consecutive natural numbers
is 132.
(A) x² + x + 132 = 0)
(B)
x2 + 2x = 132
(C)
x2 + x - 132 = 0
(D) x2 + 2x + 132 = 0
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Answer 1

Answer:

1st consecutive no. be x

2nd will be x+1

so, product

x(x+1) = 132

Ans

x²+x-132=0