Question

form an equavation whose roots are 2 and -5.​

Answer 1

Answer:

x^2 + 3x -10

Step-by-step explanation:

lets use identity 4

(x+a)(x+b)=x^2 + (a+b)x + ab

x+a=0

x=-a

x+b=0

x=-b

as its given that the roots are 2 and -5,

x=2 and x=-5

exuating these,

-a=2

a=-2

-b=-5

b=5

(x-2)(x+5) will be the factorized form of our equation.

simplifying,

x^2 (-2+5)x + (-2)(5)

x^2 +3x -10

and the roots of the equation are 2 and -5

we can verify this

p(2)=(2)^2 +3(2)-10

=4+6-10

=10-10

=0

similarly, p(-5) = (-5)^2+3(-5)-10

=25-15-10

=25-25

=0

hence proved

pls mark as brainliest as you get 25% of the points when you do.