Question

form differential equation
1.y=ax^3+bx^2

Answer 1

dy/dx=d(ax^3+bx^2)/dx
=d(ax^3)/dx+d(bx^2)dx
( d(a^n) =n a^n-1)
=a*3*x^3-1 + b*2*x^2-1
=3ax^2 + 2bx

Hope it helped you