form equation and solve .............................a no. os 56 greater than the average of its third quarter and one twelfth .find the no.
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SUPPOSE NUMBER IS X
3RD NUMBER = X/3
QUARTER = X/4
12TH NUMBER = X/12
THE NUMBER IS 56 GREATER THAN THE AVERAGE OF 3RD,4TH, AND 12TH
SET UP THE EQUATION
TOTAL OF X/3 +X/4 + X/12 = 8X/12
AVERAGE = 1/3 × 8X/12 = 8X=36
8X/36 = X— 56
8X = 36X — 36 × 56
8X — 36X = — 36× 56
28X = 36 × 56
X = 72
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