Math, asked by putch9097, 1 year ago

Form equation whose roots are 5+√3, 5-√3

Answers

Answered by ruchijain3112
3

Answer:

answer is

x*2-10x+25=0

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Answered by RakhiBhedke
15

Answer:

 \purple{x^2 - 10 + 22}

Step-by-step explanation:

By using the following formula, we can easily find the quadratic equation:

 \large{\bold{k[x^2 - (\alpha + \beta)x + (\alpha \beta)]}}

Assumption:

Let  \alpha = 5 + \sqrt{3} and let  \beta = 5 - \sqrt{3}

Now, substituting the values of α and β in the above formula,

 \large{k[x^2 - (5 + \sqrt{3} + 5 - \sqrt{3}) + (5 + \sqrt{3} \times 5 - \sqrt{3})}

 \large{k[x^2 - 10x + (25 - 3)]}

[∵ (a + b)(a - b) = a² - b²]

 \therefore \large{k[x^2 - 10x + 22]}

Substituting k = 1;

∴ The equation is x² - 10x + 22.

The required equation is x² - 10 + 22.

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