Math, asked by Nabhankhan97451, 3 months ago

Form equations and solve: The 3 angles of a triangle are xᵒ , (x+10)ᵒ , 70ᵒ . Find the measure of the two  angles of the triangle.​

Answers

Answered by luckydagar2929
0

sum of all angles in a triangle is equal to 180 degree

x⁰+(x+10)⁰+70⁰ = 180⁰

2x+80=180

2x=180-80

2x=100

x = 100/2

x=50⁰

Answered by Anonymous
0

Answer:

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Step-by-step explanation:

Let us suppose the angles ∠P, ∠Q, ∠R of a ΔPQR be x°, (x +10)°, (70)° respectively.

In ΔPQR,

∠P + ∠Q + ∠R = 180°   (Angle sum property)

x + x+10 + 70 = 180°

2x + 80° = 180°

2x = 180° - 80°

2x = 100°

x = 100/2

x = 50°

∴Measure of

∠P = x° = 50°

∠Q = (x+10)° = (50+10)° = 60°

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