Form equations and solve: The 3 angles of a triangle are xᵒ , (x+10)ᵒ , 70ᵒ . Find the measure of the two angles of the triangle.
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sum of all angles in a triangle is equal to 180 degree
x⁰+(x+10)⁰+70⁰ = 180⁰
2x+80=180
2x=180-80
2x=100
x = 100/2
x=50⁰
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Step-by-step explanation:
Let us suppose the angles ∠P, ∠Q, ∠R of a ΔPQR be x°, (x +10)°, (70)° respectively.
In ΔPQR,
∠P + ∠Q + ∠R = 180° (Angle sum property)
x + x+10 + 70 = 180°
2x + 80° = 180°
2x = 180° - 80°
2x = 100°
x = 100/2
x = 50°
∴Measure of
∠P = x° = 50°
∠Q = (x+10)° = (50+10)° = 60°
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