form polynomial with zeros 1/a and 1/b
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Answer:
hello
Step-by-step explanation:
let the zeroes of the unknow polynomial be "C" and "D"
C = 1/a
D = 1/b
Sum of zeroes = C + D
= 1/a + 1/b
= a+b / ab -------------------- i
Product of zeroes = C * D
= 1/a × 1/b
= 1 / ab --------------------- ii
Required polynomial = k [ x^2 - (sum of zeroes)x + product of zeroes]
where k = constant
= k [ x^2 - (a+b)x/ab + 1/ab ]
= k = ab
= abx^2 - (a+b)x + 1
Hence found :)
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