Form quadratic equation when one root = 3-√5, sum of roots = 6.
Answers
Answered by
12
Heya !!!
Let other zero be Beta .
Alpha = ( 3 - ✓5 )
Sum of zeroes = 6
Alpha + Beta = 6
3 - ✓5 + Beta = 6
Beta = ( 6 - 3 + ✓5 ) = ( 3 + ✓5 )
★ Product of zeroes = Alpha × Beta = ( 3 - ✓5 ) ( 3 + ✓5 ) = (3)² - (✓5)² = 9-5 = 4
Therefore,
Required quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes
=> X² - ( 6 )X +4
=> X² - 6X + 4 .
★ HOPE IT WILL HELP YOU ★
Let other zero be Beta .
Alpha = ( 3 - ✓5 )
Sum of zeroes = 6
Alpha + Beta = 6
3 - ✓5 + Beta = 6
Beta = ( 6 - 3 + ✓5 ) = ( 3 + ✓5 )
★ Product of zeroes = Alpha × Beta = ( 3 - ✓5 ) ( 3 + ✓5 ) = (3)² - (✓5)² = 9-5 = 4
Therefore,
Required quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes
=> X² - ( 6 )X +4
=> X² - 6X + 4 .
★ HOPE IT WILL HELP YOU ★
Answered by
10
Hey!!
Sum of zeroes = 6
Product of zeroes
Required polynomial
HOPE IT WILL HELPS YOU :-)
Sum of zeroes = 6
Product of zeroes
Required polynomial
HOPE IT WILL HELPS YOU :-)
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