Question

Form quadratic equation whose roots are =(1/2 ,_4)

Answer 1

$\huge\star\bold\red{ANSWER}$

$\alpha$=1/2

$\beta$=(-4)

$\star\bold\red{Then,}$

$\alpha$+$\beta$= 1/2+(-4)

=>1/2-4

=>(1-8)/2

=>-7/2

similarly,

$\alpha$×$\beta$= 1/2×(-4)

=>-4/2

=>-2

$\star\bold\red{NOW}$

p(x)= x²-($\alpha$+$\beta$)x+$\alpha$$\beta$

=> x²-(-7/2)x+(-2)

=>x²+7/2x-2 ......ans...

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Answer 2

k(x²+7/2-2)=0

Step-by-step explanation:

QUADRATIC EQUATION:

K[x²-(sum of roots)x+(product of roots)]=0

LET ROOTS BE: α and β=

α=1/2

β=-4

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Sum of roots = α+β = (1/2)-(4)

= (1-8)/2

= -7/2

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Product of roots = αβ = (1/2)×(-4)

= -2

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Putting values in equation:

k(x²-(-7/2)+(-2))=0

k(x²+7/2-2)=0