Form the differential equation of all parabolas having the vertex at origin and axis along the positive Y-axis.
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The parabolic equation would be :-
Y=x²
This is the parabolic equation.
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Answer:
= xy' - 2y = 0
Step-by-step explanation:
The equation of parabola having vertex at origin and axis along +ve y-axis is
x² = 4ay ----->(1) where a is a parameter
Differentiating w.r.t x we get,
2x = 4a. dy/dx
x = 2ay' [ where y' = dy/dx ]
=> a = x / 2y'
Putting a = x/2y' in (1) we get
=> x² = 4. x/2y . y
=> y' = 2y/x
=> xy' = 2y
=> xy' - 2y = 0
GOOD LUCK !!
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