Math, asked by yogirlmansi4445, 1 year ago

Form the differential equation of the family of hyperbolas having foci on y-axis and centre at origin.

Answers

Answered by kalashyam
7
equation of hyperbola when focus on y axis
Attachments:
Answered by sk940178
6

Answer:

y^{2} \frac{d^{2}y }{dx^{2} }=\frac{y^{2} }{x} \frac{dy}{dx} -y(\frac{dy}{dx}) ^{2}

Step-by-step explanation:

Equation of hyperbola having foci on y-axis and center at origin is given by, \frac{y^{2} }{a^{2} } -\frac{x^{2} }{b^{2} } =1 ....... (1)

Now, differentiating (1) with respect to x,

\frac{2y}{a^{2} }. \frac{dy}{dx} =\frac{2x}{b^{2} }

 \frac{dy}{dx}=\frac{a^{2} }{b^{2} } (\frac{x}{y} ) ....... (2)

Again differentiating with respect to x.

\frac{d^{2}y }{dx^{2} } =\frac{a^{2} }{b^{2} } (\frac{y-x\frac{dy}{dx} }{y^{2} } ) {From equation (2)}

y^{2} \frac{d^{2}y }{dx^{2} }=\frac{y}{x} \frac{dy}{dx}(y-x\frac{dy}{dx} )

y^{2} \frac{d^{2}y }{dx^{2} }=\frac{y^{2} }{x} \frac{dy}{dx} -y(\frac{dy}{dx}) ^{2}

Hence this is the required differential equation. (Answer)

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