Form the equation
Each of the 2 equal sides of an isosceles triangle is twice as large as the third
side. If the perimeter of the triangle is 30 cm, find the length of each side of the
triangle. (Let y be the measure of each equal side)
Answers
Let an isosceles triangle have equal sides in length of 2x cm
So, x cm be the third side of the triangle
Perimeter of the triangle =30 cm
⇒ x+2x+2x=30
⇒ 5x=30
⇒ x= 5/30
⇒ x=6
Therefore, the required sides of the isosceles triangle are 6,12 and 12 cm
Answer:
Let an isosceles triangle have equal sides in length of 2x cm
Let an isosceles triangle have equal sides in length of 2x cmSo, x cm be the third side of the triangle
Let an isosceles triangle have equal sides in length of 2x cmSo, x cm be the third side of the trianglePerimeter of the triangle =30 cm
Let an isosceles triangle have equal sides in length of 2x cmSo, x cm be the third side of the trianglePerimeter of the triangle =30 cm⇒ x+2x+2x=30
Let an isosceles triangle have equal sides in length of 2x cmSo, x cm be the third side of the trianglePerimeter of the triangle =30 cm⇒ x+2x+2x=30⇒ 5x=30
Let an isosceles triangle have equal sides in length of 2x cmSo, x cm be the third side of the trianglePerimeter of the triangle =30 cm⇒ x+2x+2x=30⇒ 5x=30⇒ x= 5/30
Let an isosceles triangle have equal sides in length of 2x cmSo, x cm be the third side of the trianglePerimeter of the triangle =30 cm⇒ x+2x+2x=30⇒ 5x=30⇒ x= 5/30⇒ x=6
Let an isosceles triangle have equal sides in length of 2x cmSo, x cm be the third side of the trianglePerimeter of the triangle =30 cm⇒ x+2x+2x=30⇒ 5x=30⇒ x= 5/30⇒ x=6Therefore, the required sides of the isosceles triangle are 6,12 and 12 cm