Form the equation for the given situation: Hasan is thrice as old as Amina. Six years ago Hasan's age was 7 times Amina's age.
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Answer:
Let the age of Salim =x and the age of the daughter =y, both in year.
Then two years back their ages are
x−2 and y−2 respectively.
∴ by the given condition
x−2=3(y−2)
⇒x−3y=−4 (i)
Again six years later their ages will be
x+6 and y+6 respectively.
∴ by the given condition
x+6=2(y+6)+4
⇒x−2y=10 (ii)
Subtracting (ii) from (i), we get
−y=−14
⇒y=14
Putting y=14 in (i), we get
x−3×14=−4
⇒x=38
So, Salim's present age =38 yrs and his daughter's present age =14 yrs.
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